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11312013313 = 33433383791
BaseRepresentation
bin10101000100011111…
…11010000000000001
31002012100112211001001
422202033322000001
5141131333411223
65110251412001
7550215345436
oct124217720001
932170484031
1011312013313
114885378037
122238454001
1310b3770503
147944cdb8d
154631729ad
hex2a23fa001

11312013313 has 4 divisors (see below), whose sum is σ = 11315400448. Its totient is φ = 11308626180.

The previous prime is 11312013281. The next prime is 11312013347. The reversal of 11312013313 is 31331021311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11312013313 - 25 = 11312013281 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11312013353) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1688553 + ... + 1695238.

It is an arithmetic number, because the mean of its divisors is an integer number (2828850112).

Almost surely, 211312013313 is an apocalyptic number.

It is an amenable number.

11312013313 is a deficient number, since it is larger than the sum of its proper divisors (3387135).

11312013313 is an equidigital number, since it uses as much as digits as its factorization.

11312013313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3387134.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 11312013313 its reverse (31331021311), we get a palindrome (42643034624).

The spelling of 11312013313 in words is "eleven billion, three hundred twelve million, thirteen thousand, three hundred thirteen".

Divisors: 1 3343 3383791 11312013313