1131203313001 has 4 divisors (see below), whose sum is σ = 1197744684372. Its totient is φ = 1064661941632.

The previous prime is 1131203312989. The next prime is 1131203313007. The reversal of 1131203313001 is 1003133021311.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 326457963225 + 804745349776 = 571365^2 + 897076^2 .

It is a cyclic number.

It is not a de Polignac number, because 1131203313001 - 2⁵ = 1131203312969 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1131203313001.

It is not an unprimeable number, because it can be changed into a prime (1131203313007) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33270685660 + ... + 33270685693.

It is an arithmetic number, because the mean of its divisors is an integer number (299436171093).

Almost surely, 2^{1131203313001} is an apocalyptic number.

It is an amenable number.

1131203313001 is a deficient number, since it is larger than the sum of its proper divisors (66541371371).

1131203313001 is an equidigital number, since it uses as much as digits as its factorization.

1131203313001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 66541371370.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 1131203313001 its reverse (1003133021311), we get a palindrome (2134336334312).

The spelling of 1131203313001 in words is "one trillion, one hundred thirty-one billion, two hundred three million, three hundred thirteen thousand, one".