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11312033241 = 33770677747
BaseRepresentation
bin10101000100011111…
…11110110111011001
31002012100120211101010
422202033332313121
5141131340030431
65110252044133
7550215460515
oct124217766731
932170524333
1011312033241
114885391003
122238463649
1310b37795c2
147944d7145
15463178846
hex2a23fedd9

11312033241 has 4 divisors (see below), whose sum is σ = 15082710992. Its totient is φ = 7541355492.

The previous prime is 11312033221. The next prime is 11312033279. The reversal of 11312033241 is 14233021311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14233021311 = 34744340437.

It is not a de Polignac number, because 11312033241 - 27 = 11312033113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11312033221) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1885338871 + ... + 1885338876.

It is an arithmetic number, because the mean of its divisors is an integer number (3770677748).

Almost surely, 211312033241 is an apocalyptic number.

It is an amenable number.

11312033241 is a deficient number, since it is larger than the sum of its proper divisors (3770677751).

11312033241 is an equidigital number, since it uses as much as digits as its factorization.

11312033241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3770677750.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 11312033241 its reverse (14233021311), we get a palindrome (25545054552).

The spelling of 11312033241 in words is "eleven billion, three hundred twelve million, thirty-three thousand, two hundred forty-one".

Divisors: 1 3 3770677747 11312033241