Base | Representation |
---|---|
bin | 10101000100100000… |
… | …01111001110001001 |
3 | 1002012100201020021022 |
4 | 22202100033032021 |
5 | 141131344201413 |
6 | 5110253322225 |
7 | 550216160030 |
oct | 124220171611 |
9 | 32170636238 |
10 | 11312100233 |
11 | 4885427375 |
12 | 2238496375 |
13 | 10b37a0c45 |
14 | 794513717 |
15 | 46318d608 |
hex | 2a240f389 |
11312100233 has 4 divisors (see below), whose sum is σ = 12928114560. Its totient is φ = 9696085908.
The previous prime is 11312100227. The next prime is 11312100253. The reversal of 11312100233 is 33200121311.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 11312100233 - 216 = 11312034697 is a prime.
It is a super-2 number, since 2×113121002332 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11312100253) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 808007153 + ... + 808007166.
It is an arithmetic number, because the mean of its divisors is an integer number (3232028640).
Almost surely, 211312100233 is an apocalyptic number.
It is an amenable number.
11312100233 is a deficient number, since it is larger than the sum of its proper divisors (1616014327).
11312100233 is an equidigital number, since it uses as much as digits as its factorization.
11312100233 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1616014326.
The product of its (nonzero) digits is 108, while the sum is 17.
Adding to 11312100233 its reverse (33200121311), we get a palindrome (44512221544).
The spelling of 11312100233 in words is "eleven billion, three hundred twelve million, one hundred thousand, two hundred thirty-three".
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