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1131212435435 = 52931710745137
BaseRepresentation
bin10000011101100001100…
…000111110111111101011
311000010212010202202211222
4100131201200332333223
5122013210340413220
62223401040212255
7144504333023405
oct20354140767753
94003763682758
101131212435435
113a6820a24785
121632a090a08b
13828993c9a94
143ca7295bb75
151e65ac6ee25
hex1076183efeb

1131212435435 has 16 divisors (see below), whose sum is σ = 1362197674656. Its totient is φ = 901808613888.

The previous prime is 1131212435417. The next prime is 1131212435471. The reversal of 1131212435435 is 5345342121311.

It is a cyclic number.

It is not a de Polignac number, because 1131212435435 - 210 = 1131212434411 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1131212435395 and 1131212435404.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 25039187 + ... + 25084323.

It is an arithmetic number, because the mean of its divisors is an integer number (85137354666).

Almost surely, 21131212435435 is an apocalyptic number.

1131212435435 is a deficient number, since it is larger than the sum of its proper divisors (230985239221).

1131212435435 is a wasteful number, since it uses less digits than its factorization.

1131212435435 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 62542.

The product of its digits is 43200, while the sum is 35.

Adding to 1131212435435 its reverse (5345342121311), we get a palindrome (6476554556746).

The spelling of 1131212435435 in words is "one trillion, one hundred thirty-one billion, two hundred twelve million, four hundred thirty-five thousand, four hundred thirty-five".

Divisors: 1 5 293 1465 17107 45137 85535 225685 5012351 13225141 25061755 66125705 772158659 3860793295 226242487087 1131212435435