Base | Representation |
---|---|
bin | 10000011101100001111… |
… | …110100110101110000011 |
3 | 11000010212200101021021102 |
4 | 100131201332212232003 |
5 | 122013214332402243 |
6 | 2223401514445015 |
7 | 144504456023513 |
oct | 20354176465603 |
9 | 4003780337242 |
10 | 1131220200323 |
11 | 3a6825348644 |
12 | 1632a343376b |
13 | 8289abb81a5 |
14 | 3ca739bd843 |
15 | 1e65b7a59b8 |
hex | 10761fa6b83 |
1131220200323 has 4 divisors (see below), whose sum is σ = 1131222362568. Its totient is φ = 1131218038080.
The previous prime is 1131220200307. The next prime is 1131220200343. The reversal of 1131220200323 is 3230020221311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1131220200323 - 24 = 1131220200307 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1131220200295 and 1131220200304.
It is not an unprimeable number, because it can be changed into a prime (1131220200343) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 249683 + ... + 1524723.
It is an arithmetic number, because the mean of its divisors is an integer number (282805590642).
Almost surely, 21131220200323 is an apocalyptic number.
1131220200323 is a deficient number, since it is larger than the sum of its proper divisors (2162245).
1131220200323 is an equidigital number, since it uses as much as digits as its factorization.
1131220200323 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2162244.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 1131220200323 its reverse (3230020221311), we get a palindrome (4361240421634).
The spelling of 1131220200323 in words is "one trillion, one hundred thirty-one billion, two hundred twenty million, two hundred thousand, three hundred twenty-three".
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