11312410433 has 4 divisors (see below), whose sum is σ = 11381811888. Its totient is φ = 11243008980.

The previous prime is 11312410429. The next prime is 11312410441. The reversal of 11312410433 is 33401421311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11312410433 - 2² = 11312410429 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11312410399 and 11312410408.

It is not an unprimeable number, because it can be changed into a prime (11312410463) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34700483 + ... + 34700808.

It is an arithmetic number, because the mean of its divisors is an integer number (2845452972).

Almost surely, 2^11312410433 is an apocalyptic number.

It is an amenable number.

11312410433 is a deficient number, since it is larger than the sum of its proper divisors (69401455).

11312410433 is an equidigital number, since it uses as much as digits as its factorization.

11312410433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 69401454.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 11312410433 its reverse (33401421311), we get a palindrome (44713831744).

The spelling of 11312410433 in words is "eleven billion, three hundred twelve million, four hundred ten thousand, four hundred thirty-three".