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11312411403 = 318472041583
BaseRepresentation
bin10101000100100010…
…11011001100001011
31002012101022001010010
422202101123030023
5141131434131103
65110304123003
7550221624156
oct124221331413
932171261103
1011312411403
11488561a137
122238606463
1310b387c777
14794594c9d
15463200903
hex2a245b30b

11312411403 has 8 divisors (see below), whose sum is σ = 15091388928. Its totient is φ = 7537520744.

The previous prime is 11312411293. The next prime is 11312411417. The reversal of 11312411403 is 30411421311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11312411403 - 216 = 11312345867 is a prime.

It is a super-3 number, since 3×113124114033 (a number of 31 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 11312411403.

It is not an unprimeable number, because it can be changed into a prime (11312411423) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1015251 + ... + 1026332.

It is an arithmetic number, because the mean of its divisors is an integer number (1886423616).

Almost surely, 211312411403 is an apocalyptic number.

11312411403 is a deficient number, since it is larger than the sum of its proper divisors (3778977525).

11312411403 is a wasteful number, since it uses less digits than its factorization.

11312411403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2043433.

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 11312411403 its reverse (30411421311), we get a palindrome (41723832714).

The spelling of 11312411403 in words is "eleven billion, three hundred twelve million, four hundred eleven thousand, four hundred three".

Divisors: 1 3 1847 5541 2041583 6124749 3770803801 11312411403