Base | Representation |
---|---|
bin | 10000011101100011011… |
… | …011000000101110110001 |
3 | 11000010221100221222001211 |
4 | 100131203123000232301 |
5 | 122013242033032423 |
6 | 2223404142000121 |
7 | 144505201644016 |
oct | 20354333005661 |
9 | 4003840858054 |
10 | 1131244424113 |
11 | 3a6837a93301 |
12 | 1632ab576041 |
13 | 828a2c19cab |
14 | 3ca76cc770d |
15 | 1e65d98d10d |
hex | 107636c0bb1 |
1131244424113 has 8 divisors (see below), whose sum is σ = 1150436289600. Its totient is φ = 1112053166448.
The previous prime is 1131244424041. The next prime is 1131244424129. The reversal of 1131244424113 is 3114244421311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1131244424113 - 221 = 1131242326961 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1131244424173) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5168148 + ... + 5382586.
It is an arithmetic number, because the mean of its divisors is an integer number (143804536200).
Almost surely, 21131244424113 is an apocalyptic number.
It is an amenable number.
1131244424113 is a deficient number, since it is larger than the sum of its proper divisors (19191865487).
1131244424113 is an equidigital number, since it uses as much as digits as its factorization.
1131244424113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 303911.
The product of its digits is 9216, while the sum is 31.
Adding to 1131244424113 its reverse (3114244421311), we get a palindrome (4245488845424).
The spelling of 1131244424113 in words is "one trillion, one hundred thirty-one billion, two hundred forty-four million, four hundred twenty-four thousand, one hundred thirteen".
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