Base | Representation |
---|---|
bin | 10101000100100111… |
… | …01010111110000011 |
3 | 1002012102101221221222 |
4 | 22202103222332003 |
5 | 141132112002243 |
6 | 5110324505255 |
7 | 550226626142 |
oct | 124223527603 |
9 | 32172357858 |
10 | 11313000323 |
11 | 4885991649 |
12 | 223884b22b |
13 | 10b3a27841 |
14 | 7946a9759 |
15 | 4632ba168 |
hex | 2a24eaf83 |
11313000323 has 4 divisors (see below), whose sum is σ = 11349144408. Its totient is φ = 11276856240.
The previous prime is 11313000313. The next prime is 11313000367. The reversal of 11313000323 is 32300031311.
11313000323 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11313000323 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11313000313) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18071573 + ... + 18072198.
It is an arithmetic number, because the mean of its divisors is an integer number (2837286102).
Almost surely, 211313000323 is an apocalyptic number.
11313000323 is a deficient number, since it is larger than the sum of its proper divisors (36144085).
11313000323 is an equidigital number, since it uses as much as digits as its factorization.
11313000323 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 36144084.
The product of its (nonzero) digits is 162, while the sum is 17.
Adding to 11313000323 its reverse (32300031311), we get a palindrome (43613031634).
The spelling of 11313000323 in words is "eleven billion, three hundred thirteen million, three hundred twenty-three", and thus it is an aban number.
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