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1131300103321 = 3113637620911
BaseRepresentation
bin10000011101100110101…
…111011010010010011001
311000011002020201202120201
4100131212233122102121
5122013400311301241
62223413451222201
7144506446134043
oct20354657322231
94004066652521
101131300103321
113a6866462983
12163306147961
13828b161337b
143ca8045ca93
151e6637da931
hex10766bda499

1131300103321 has 4 divisors (see below), whose sum is σ = 1134937724544. Its totient is φ = 1127662482100.

The previous prime is 1131300103277. The next prime is 1131300103331. The reversal of 1131300103321 is 1233010031311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1131300103321 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1131300103331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1818810145 + ... + 1818810766.

It is an arithmetic number, because the mean of its divisors is an integer number (283734431136).

Almost surely, 21131300103321 is an apocalyptic number.

It is an amenable number.

1131300103321 is a deficient number, since it is larger than the sum of its proper divisors (3637621223).

1131300103321 is an equidigital number, since it uses as much as digits as its factorization.

1131300103321 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3637621222.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 1131300103321 its reverse (1233010031311), we get a palindrome (2364310134632).

The spelling of 1131300103321 in words is "one trillion, one hundred thirty-one billion, three hundred million, one hundred three thousand, three hundred twenty-one".

Divisors: 1 311 3637620911 1131300103321