113130012202033 has 4 divisors (see below), whose sum is σ = 113136998571108. Its totient is φ = 113123025832960.

The previous prime is 113130012202003. The next prime is 113130012202063. The reversal of 113130012202033 is 330202210031311.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (113130012202003) and next prime (113130012202063).

It can be written as a sum of positive squares in 2 ways, for example, as 108453208043569 + 4676804158464 = 10414087^2 + 2162592^2 .

It is a cyclic number.

It is not a de Polignac number, because 113130012202033 - 2⁵ = 113130012202001 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 113130012201995 and 113130012202013.

It is not an unprimeable number, because it can be changed into a prime (113130012202003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3493160248 + ... + 3493192633.

It is an arithmetic number, because the mean of its divisors is an integer number (28284249642777).

Almost surely, 2^{113130012202033} is an apocalyptic number.

It is an amenable number.

113130012202033 is a deficient number, since it is larger than the sum of its proper divisors (6986369075).

113130012202033 is an equidigital number, since it uses as much as digits as its factorization.

113130012202033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6986369074.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 113130012202033 its reverse (330202210031311), we get a palindrome (443332222233344).

The spelling of 113130012202033 in words is "one hundred thirteen trillion, one hundred thirty billion, twelve million, two hundred two thousand, thirty-three".