11313001301033 has 4 divisors (see below), whose sum is σ = 11908422422160. Its totient is φ = 10717580179908.

The previous prime is 11313001301011. The next prime is 11313001301051. The reversal of 11313001301033 is 33010310031311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11313001301033 - 2⁶ = 11313001300969 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11313001300996 and 11313001301014.

It is not an unprimeable number, because it can be changed into a prime (11313001301333) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 297710560535 + ... + 297710560572.

It is an arithmetic number, because the mean of its divisors is an integer number (2977105605540).

Almost surely, 2^{11313001301033} is an apocalyptic number.

It is an amenable number.

11313001301033 is a deficient number, since it is larger than the sum of its proper divisors (595421121127).

11313001301033 is an equidigital number, since it uses as much as digits as its factorization.

11313001301033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 595421121126.

The product of its (nonzero) digits is 243, while the sum is 20.

Adding to 11313001301033 its reverse (33010310031311), we get a palindrome (44323311332344).

The spelling of 11313001301033 in words is "eleven trillion, three hundred thirteen billion, one million, three hundred one thousand, thirty-three".