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11313003013211 = 17665470765483
BaseRepresentation
bin1010010010100000001110…
…0001101010010001011011
31111001111211122001012212102
42210220003201222101123
52440323012232410321
640021042152234015
72245223521663334
oct244500341522133
944044748035772
1011313003013211
1136718aa2a9519
12132865199b90b
13640a7213b003
142b17a35c928b
151494256b2c0b
hexa4a0386a45b

11313003013211 has 4 divisors (see below), whose sum is σ = 11978473778712. Its totient is φ = 10647532247712.

The previous prime is 11313003013183. The next prime is 11313003013217. The reversal of 11313003013211 is 11231030031311.

It is a semiprime because it is the product of two primes.

It is a de Polignac number, because none of the positive numbers 2k-11313003013211 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11313003013217) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 332735382725 + ... + 332735382758.

It is an arithmetic number, because the mean of its divisors is an integer number (2994618444678).

Almost surely, 211313003013211 is an apocalyptic number.

11313003013211 is a deficient number, since it is larger than the sum of its proper divisors (665470765501).

11313003013211 is an equidigital number, since it uses as much as digits as its factorization.

11313003013211 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 665470765500.

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 11313003013211 its reverse (11231030031311), we get a palindrome (22544033044522).

The spelling of 11313003013211 in words is "eleven trillion, three hundred thirteen billion, three million, thirteen thousand, two hundred eleven".

Divisors: 1 17 665470765483 11313003013211