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113130047355 = 3513580154089
BaseRepresentation
bin110100101011100010…
…0111000011101111011
3101211000020010212010220
41221113010320131323
53323142243003410
6123545441311123
711113316351643
oct1512704703573
9354006125126
10113130047355
1143a83a65006
1219b130354a3
13a88bb15630
145692b9d523
152e21cc9070
hex1a5713877b

113130047355 has 16 divisors (see below), whose sum is σ = 194931774240. Its totient is φ = 55694792448.

The previous prime is 113130047341. The next prime is 113130047467. The reversal of 113130047355 is 553740031311.

It is not a de Polignac number, because 113130047355 - 26 = 113130047291 is a prime.

It is a super-2 number, since 2×1131300473552 (a number of 23 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 290076850 + ... + 290077239.

It is an arithmetic number, because the mean of its divisors is an integer number (12183235890).

Almost surely, 2113130047355 is an apocalyptic number.

113130047355 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

113130047355 is a deficient number, since it is larger than the sum of its proper divisors (81801726885).

113130047355 is a wasteful number, since it uses less digits than its factorization.

113130047355 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 580154110.

The product of its (nonzero) digits is 18900, while the sum is 33.

Adding to 113130047355 its reverse (553740031311), we get a palindrome (666870078666).

The spelling of 113130047355 in words is "one hundred thirteen billion, one hundred thirty million, forty-seven thousand, three hundred fifty-five".

Divisors: 1 3 5 13 15 39 65 195 580154089 1740462267 2900770445 7542003157 8702311335 22626009471 37710015785 113130047355