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11313011203 = 13870231631
BaseRepresentation
bin10101000100100111…
…01101101000000011
31002012102102111212221
422202103231220003
5141132112324303
65110325031511
7550230002644
oct124223555003
932172374787
1011313011203
11488599983a
122238855597
1310b3a2c790
147946ad6cb
154632bd4bd
hex2a24eda03

11313011203 has 4 divisors (see below), whose sum is σ = 12183242848. Its totient is φ = 10442779560.

The previous prime is 11313011201. The next prime is 11313011207. The reversal of 11313011203 is 30211031311.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30211031311 = 139217345549.

It is a cyclic number.

It is not a de Polignac number, because 11313011203 - 21 = 11313011201 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11313011201) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 435115803 + ... + 435115828.

It is an arithmetic number, because the mean of its divisors is an integer number (3045810712).

Almost surely, 211313011203 is an apocalyptic number.

11313011203 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

11313011203 is a deficient number, since it is larger than the sum of its proper divisors (870231645).

11313011203 is an equidigital number, since it uses as much as digits as its factorization.

11313011203 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 870231644.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 11313011203 its reverse (30211031311), we get a palindrome (41524042514).

The spelling of 11313011203 in words is "eleven billion, three hundred thirteen million, eleven thousand, two hundred three".

Divisors: 1 13 870231631 11313011203