Base | Representation |
---|---|
bin | 10101000100100111… |
… | …10010001111110011 |
3 | 1002012102110110211222 |
4 | 22202103302033303 |
5 | 141132113431011 |
6 | 5110325255255 |
7 | 550230112064 |
oct | 124223621763 |
9 | 32172413758 |
10 | 11313030131 |
11 | 4885a01a87 |
12 | 223886452b |
13 | 10b3a38290 |
14 | 7946b656b |
15 | 4632c3ddb |
hex | 2a24f23f3 |
11313030131 has 4 divisors (see below), whose sum is σ = 12183263232. Its totient is φ = 10442797032.
The previous prime is 11313030121. The next prime is 11313030133. The reversal of 11313030131 is 13103031311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11313030131 - 218 = 11312767987 is a prime.
It is a super-2 number, since 2×113130301312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11313030133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 435116531 + ... + 435116556.
It is an arithmetic number, because the mean of its divisors is an integer number (3045815808).
Almost surely, 211313030131 is an apocalyptic number.
11313030131 is a deficient number, since it is larger than the sum of its proper divisors (870233101).
11313030131 is an equidigital number, since it uses as much as digits as its factorization.
11313030131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 870233100.
The product of its (nonzero) digits is 81, while the sum is 17.
Adding to 11313030131 its reverse (13103031311), we get a palindrome (24416061442).
The spelling of 11313030131 in words is "eleven billion, three hundred thirteen million, thirty thousand, one hundred thirty-one".
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