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113131101123 = 3212570122347
BaseRepresentation
bin110100101011100100…
…0111001101111000011
3101211000022010101122100
41221113020321233003
53323143030213443
6123545520041443
711113331331105
oct1512710715703
9354008111570
10113131101123
1143a84614797
1219b13463283
13a88c0c4171
145692d95575
152e21e363d3
hex1a57239bc3

113131101123 has 6 divisors (see below), whose sum is σ = 163411590524. Its totient is φ = 75420734076.

The previous prime is 113131101113. The next prime is 113131101151. The reversal of 113131101123 is 321101131311.

It is not a de Polignac number, because 113131101123 - 214 = 113131084739 is a prime.

It is a super-2 number, since 2×1131311011232 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 113131101096 and 113131101105.

It is not an unprimeable number, because it can be changed into a prime (113131101113) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 6285061165 + ... + 6285061182.

Almost surely, 2113131101123 is an apocalyptic number.

113131101123 is a deficient number, since it is larger than the sum of its proper divisors (50280489401).

113131101123 is a wasteful number, since it uses less digits than its factorization.

113131101123 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12570122353 (or 12570122350 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 18.

Adding to 113131101123 its reverse (321101131311), we get a palindrome (434232232434).

The spelling of 113131101123 in words is "one hundred thirteen billion, one hundred thirty-one million, one hundred one thousand, one hundred twenty-three".

Divisors: 1 3 9 12570122347 37710367041 113131101123