11313114401 has 4 divisors (see below), whose sum is σ = 11313478212. Its totient is φ = 11312750592.

The previous prime is 11313114383. The next prime is 11313114403. The reversal of 11313114401 is 10441131311.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1763916001 + 9549198400 = 41999^2 + 97720^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11313114401 is a prime.

It is a super-2 number, since 2×11313114401² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (11313114403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 130400 + ... + 199073.

It is an arithmetic number, because the mean of its divisors is an integer number (2828369553).

Almost surely, 2^11313114401 is an apocalyptic number.

It is an amenable number.

11313114401 is a deficient number, since it is larger than the sum of its proper divisors (363811).

11313114401 is an equidigital number, since it uses as much as digits as its factorization.

11313114401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 363810.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 11313114401 its reverse (10441131311), we get a palindrome (21754245712).

The spelling of 11313114401 in words is "eleven billion, three hundred thirteen million, one hundred fourteen thousand, four hundred one".