11313121433 has 4 divisors (see below), whose sum is σ = 11362523940. Its totient is φ = 11263718928.

The previous prime is 11313121429. The next prime is 11313121459. The reversal of 11313121433 is 33412131311.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 10094622784 + 1218498649 = 100472^2 + 34907^2 .

It is a cyclic number.

It is not a de Polignac number, because 11313121433 - 2² = 11313121429 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11313121399 and 11313121408.

It is not an unprimeable number, because it can be changed into a prime (11313121423) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24700910 + ... + 24701367.

It is an arithmetic number, because the mean of its divisors is an integer number (2840630985).

Almost surely, 2^11313121433 is an apocalyptic number.

It is an amenable number.

11313121433 is a deficient number, since it is larger than the sum of its proper divisors (49402507).

11313121433 is an equidigital number, since it uses as much as digits as its factorization.

11313121433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 49402506.

The product of its digits is 648, while the sum is 23.

Adding to 11313121433 its reverse (33412131311), we get a palindrome (44725252744).

The spelling of 11313121433 in words is "eleven billion, three hundred thirteen million, one hundred twenty-one thousand, four hundred thirty-three".