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1131313123003 = 7161616160429
BaseRepresentation
bin10000011101100111100…
…001000100111010111011
311000011010011020020020011
4100131213201010322323
5122013412124414003
62223415034242351
7144506664611230
oct20354741047273
94004104206204
101131313123003
113a6872845848
1216330a5863b7
13828b422151b
143ca8208b787
151e664a0d46d
hex10767844ebb

1131313123003 has 4 divisors (see below), whose sum is σ = 1292929283440. Its totient is φ = 969696962568.

The previous prime is 1131313122997. The next prime is 1131313123007. The reversal of 1131313123003 is 3003213131311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1131313123003 - 225 = 1131279568571 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1131313123007) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 80808080208 + ... + 80808080221.

It is an arithmetic number, because the mean of its divisors is an integer number (323232320860).

Almost surely, 21131313123003 is an apocalyptic number.

1131313123003 is a deficient number, since it is larger than the sum of its proper divisors (161616160437).

1131313123003 is an equidigital number, since it uses as much as digits as its factorization.

1131313123003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 161616160436.

The product of its (nonzero) digits is 486, while the sum is 22.

Adding to 1131313123003 its reverse (3003213131311), we get a palindrome (4134526254314).

The spelling of 1131313123003 in words is "one trillion, one hundred thirty-one billion, three hundred thirteen million, one hundred twenty-three thousand, three".

Divisors: 1 7 161616160429 1131313123003