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113132103113 = 71222442393
BaseRepresentation
bin110100101011100110…
…0101110010111001001
3101211000101000022010002
41221113030232113021
53323143304244423
6123545553332345
711113343003261
oct1512714562711
9354011008102
10113132103113
1143a85139587
1219b138670b5
13a88c385263
1456931767a1
152e22083228
hex1a5732e5c9

113132103113 has 6 divisors (see below), whose sum is σ = 114747960522. Its totient is φ = 111538688240.

The previous prime is 113132103103. The next prime is 113132103187. The reversal of 113132103113 is 311301231311.

It can be written as a sum of positive squares in only one way, i.e., 80172789904 + 32959313209 = 283148^2 + 181547^2 .

It is not a de Polignac number, because 113132103113 - 214 = 113132086729 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (113132103103) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 11216156 + ... + 11226237.

It is an arithmetic number, because the mean of its divisors is an integer number (19124660087).

Almost surely, 2113132103113 is an apocalyptic number.

It is an amenable number.

113132103113 is a deficient number, since it is larger than the sum of its proper divisors (1615857409).

113132103113 is an frugal number, since it uses more digits than its factorization.

113132103113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 22442535 (or 22442464 counting only the distinct ones).

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 113132103113 its reverse (311301231311), we get a palindrome (424433334424).

The spelling of 113132103113 in words is "one hundred thirteen billion, one hundred thirty-two million, one hundred three thousand, one hundred thirteen".

Divisors: 1 71 5041 22442393 1593409903 113132103113