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1131321212011 = 4332612751067
BaseRepresentation
bin10000011101100111111…
…111111011110001101011
311000011010201110012021001
4100131213333323301223
5122013421212241021
62223415523455431
7144510123431314
oct20354777736153
94004121405231
101131321212011
113a6877370181
12163311227577
13828b5ac4313
143ca8319560b
151e6655aa091
hex10767ffbc6b

1131321212011 has 4 divisors (see below), whose sum is σ = 1133933963512. Its totient is φ = 1128708460512.

The previous prime is 1131321211991. The next prime is 1131321212029. The reversal of 1131321212011 is 1102121231311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1131321212011 - 233 = 1122731277419 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1131321212011.

It is not an unprimeable number, because it can be changed into a prime (1131321212041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1306375101 + ... + 1306375966.

It is an arithmetic number, because the mean of its divisors is an integer number (283483490878).

Almost surely, 21131321212011 is an apocalyptic number.

1131321212011 is a deficient number, since it is larger than the sum of its proper divisors (2612751501).

1131321212011 is an equidigital number, since it uses as much as digits as its factorization.

1131321212011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2612751500.

The product of its (nonzero) digits is 72, while the sum is 19.

Adding to 1131321212011 its reverse (1102121231311), we get a palindrome (2233442443322).

The spelling of 1131321212011 in words is "one trillion, one hundred thirty-one billion, three hundred twenty-one million, two hundred twelve thousand, eleven".

Divisors: 1 433 2612751067 1131321212011