Base | Representation |
---|---|
bin | 10101000100101001… |
… | …00000101000011001 |
3 | 1002012102211010110122 |
4 | 22202110200220121 |
5 | 141132141020441 |
6 | 5110333323025 |
7 | 550231533020 |
oct | 124224405031 |
9 | 32172733418 |
10 | 11313220121 |
11 | 48860217a5 |
12 | 2238936475 |
13 | 10b3aa38b8 |
14 | 7947258b7 |
15 | 46331034b |
hex | 2a2520a19 |
11313220121 has 4 divisors (see below), whose sum is σ = 12929394432. Its totient is φ = 9697045812.
The previous prime is 11313220069. The next prime is 11313220213. The reversal of 11313220121 is 12102231311.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 11313220121 - 210 = 11313219097 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 11313220121.
It is not an unprimeable number, because it can be changed into a prime (11313220021) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 808087145 + ... + 808087158.
It is an arithmetic number, because the mean of its divisors is an integer number (3232348608).
Almost surely, 211313220121 is an apocalyptic number.
It is an amenable number.
11313220121 is a deficient number, since it is larger than the sum of its proper divisors (1616174311).
11313220121 is an equidigital number, since it uses as much as digits as its factorization.
11313220121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1616174310.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 11313220121 its reverse (12102231311), we get a palindrome (23415451432).
The spelling of 11313220121 in words is "eleven billion, three hundred thirteen million, two hundred twenty thousand, one hundred twenty-one".
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