Base | Representation |
---|---|
bin | 10101000100101001… |
… | …00001110111000011 |
3 | 1002012102211101101002 |
4 | 22202110201313003 |
5 | 141132141201110 |
6 | 5110333402215 |
7 | 550231553501 |
oct | 124224416703 |
9 | 32172741332 |
10 | 11313225155 |
11 | 4886025561 |
12 | 223893936b |
13 | 10b3aa5c8b |
14 | 794727671 |
15 | 463311aa5 |
hex | 2a2521dc3 |
11313225155 has 4 divisors (see below), whose sum is σ = 13575870192. Its totient is φ = 9050580120.
The previous prime is 11313225113. The next prime is 11313225173. The reversal of 11313225155 is 55152231311.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 11313225155 - 28 = 11313224899 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1131322511 + ... + 1131322520.
It is an arithmetic number, because the mean of its divisors is an integer number (3393967548).
Almost surely, 211313225155 is an apocalyptic number.
11313225155 is a deficient number, since it is larger than the sum of its proper divisors (2262645037).
11313225155 is an equidigital number, since it uses as much as digits as its factorization.
11313225155 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2262645036.
The product of its digits is 4500, while the sum is 29.
Adding to 11313225155 its reverse (55152231311), we get a palindrome (66465456466).
The spelling of 11313225155 in words is "eleven billion, three hundred thirteen million, two hundred twenty-five thousand, one hundred fifty-five".
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