113132434124011 has 8 divisors (see below), whose sum is σ = 116343555047120. Its totient is φ = 109929391494048.

The previous prime is 113132434123991. The next prime is 113132434124077. The reversal of 113132434124011 is 110421434231311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 113132434124011 - 2⁵ = 113132434123979 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (113132434122011) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2019544881 + ... + 2019600898.

It is an arithmetic number, because the mean of its divisors is an integer number (14542944380890).

Almost surely, 2^{113132434124011} is an apocalyptic number.

113132434124011 is a deficient number, since it is larger than the sum of its proper divisors (3211120923109).

113132434124011 is an equidigital number, since it uses as much as digits as its factorization.

113132434124011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4039146573.

The product of its (nonzero) digits is 6912, while the sum is 31.

Adding to 113132434124011 its reverse (110421434231311), we get a palindrome (223553868355322).

The spelling of 113132434124011 in words is "one hundred thirteen trillion, one hundred thirty-two billion, four hundred thirty-four million, one hundred twenty-four thousand, eleven".