Base | Representation |
---|---|
bin | 10101000100101001… |
… | …10100001000100011 |
3 | 1002012102222012001020 |
4 | 22202110310020203 |
5 | 141132201100003 |
6 | 5110335140523 |
7 | 550232314635 |
oct | 124224641043 |
9 | 32172865036 |
10 | 11313300003 |
11 | 4886076815 |
12 | 2238974743 |
13 | 10b3b01075 |
14 | 794746a55 |
15 | 463328d53 |
hex | 2a2534223 |
11313300003 has 4 divisors (see below), whose sum is σ = 15084400008. Its totient is φ = 7542200000.
The previous prime is 11313299989. The next prime is 11313300133. The reversal of 11313300003 is 30000331311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11313300003 - 210 = 11313298979 is a prime.
It is not an unprimeable number, because it can be changed into a prime (11313300503) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1885549998 + ... + 1885550003.
It is an arithmetic number, because the mean of its divisors is an integer number (3771100002).
Almost surely, 211313300003 is an apocalyptic number.
11313300003 is a deficient number, since it is larger than the sum of its proper divisors (3771100005).
11313300003 is an equidigital number, since it uses as much as digits as its factorization.
11313300003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3771100004.
The product of its (nonzero) digits is 81, while the sum is 15.
Adding to 11313300003 its reverse (30000331311), we get a palindrome (41313631314).
The spelling of 11313300003 in words is "eleven billion, three hundred thirteen million, three hundred thousand, three".
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