Base | Representation |
---|---|
bin | 10000011101101000100… |
… | …001100000001110000001 |
3 | 11000011011100000021121210 |
4 | 100131220201200032001 |
5 | 122013430440341113 |
6 | 2223420440240333 |
7 | 144510261302334 |
oct | 20355041401601 |
9 | 4004140007553 |
10 | 1131330012033 |
11 | 3a6881330821 |
12 | 1633141700a9 |
13 | 828b7885930 |
14 | 3ca8440661b |
15 | 1e6662476c3 |
hex | 10768860381 |
1131330012033 has 16 divisors (see below), whose sum is σ = 1624677143040. Its totient is φ = 696115964544.
The previous prime is 1131330011971. The next prime is 1131330012067. The reversal of 1131330012033 is 3302100331311.
It is not a de Polignac number, because 1131330012033 - 26 = 1131330011969 is a prime.
It is a super-2 number, since 2×11313300120332 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1131330012433) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1498641 + ... + 2123342.
It is an arithmetic number, because the mean of its divisors is an integer number (101542321440).
Almost surely, 21131330012033 is an apocalyptic number.
1131330012033 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
1131330012033 is a deficient number, since it is larger than the sum of its proper divisors (493347131007).
1131330012033 is a wasteful number, since it uses less digits than its factorization.
1131330012033 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3630008.
The product of its (nonzero) digits is 486, while the sum is 21.
Adding to 1131330012033 its reverse (3302100331311), we get a palindrome (4433430343344).
The spelling of 1131330012033 in words is "one trillion, one hundred thirty-one billion, three hundred thirty million, twelve thousand, thirty-three".
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