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11313305545 = 54994534391
BaseRepresentation
bin10101000100101001…
…10101011111001001
31002012102222110122111
422202110311133021
5141132201234140
65110335222321
7550232340043
oct124224653711
932172873574
1011313305545
11488607a9a3
1222389779a1
1310b3b03749
14794748a93
1546332a7ea
hex2a25357c9

11313305545 has 8 divisors (see below), whose sum is σ = 13603176000. Its totient is φ = 9032504880.

The previous prime is 11313305543. The next prime is 11313305551. The reversal of 11313305545 is 54550331311.

11313305545 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 11313305545 - 21 = 11313305543 is a prime.

It is not an unprimeable number, because it can be changed into a prime (11313305543) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2264701 + ... + 2269690.

It is an arithmetic number, because the mean of its divisors is an integer number (1700397000).

Almost surely, 211313305545 is an apocalyptic number.

It is an amenable number.

11313305545 is a deficient number, since it is larger than the sum of its proper divisors (2289870455).

11313305545 is an equidigital number, since it uses as much as digits as its factorization.

11313305545 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4534895.

The product of its (nonzero) digits is 13500, while the sum is 31.

Adding to 11313305545 its reverse (54550331311), we get a palindrome (65863636856).

The spelling of 11313305545 in words is "eleven billion, three hundred thirteen million, three hundred five thousand, five hundred forty-five".

Divisors: 1 5 499 2495 4534391 22671955 2262661109 11313305545