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11313312113 = 61185464133
BaseRepresentation
bin10101000100101001…
…10111000101110001
31002012102222210122202
422202110313011301
5141132201441423
65110335312545
7550232365145
oct124224670561
932172883582
1011313312113
114886084924
12223897b755
1310b3b0672c
1479474b225
1546332c728
hex2a2537171

11313312113 has 4 divisors (see below), whose sum is σ = 11498776308. Its totient is φ = 11127847920.

The previous prime is 11313312103. The next prime is 11313312121. The reversal of 11313312113 is 31121331311.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 854568289 + 10458743824 = 29233^2 + 102268^2 .

It is a cyclic number.

It is not a de Polignac number, because 11313312113 - 24 = 11313312097 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (11313312103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 92732006 + ... + 92732127.

It is an arithmetic number, because the mean of its divisors is an integer number (2874694077).

Almost surely, 211313312113 is an apocalyptic number.

It is an amenable number.

11313312113 is a deficient number, since it is larger than the sum of its proper divisors (185464195).

11313312113 is an equidigital number, since it uses as much as digits as its factorization.

11313312113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 185464194.

The product of its digits is 162, while the sum is 20.

Adding to 11313312113 its reverse (31121331311), we get a palindrome (42434643424).

The spelling of 11313312113 in words is "eleven billion, three hundred thirteen million, three hundred twelve thousand, one hundred thirteen".

Divisors: 1 61 185464133 11313312113