Base | Representation |
---|---|
bin | 10101000100101001… |
… | …11001000000111001 |
3 | 1002012110000012110121 |
4 | 22202110321000321 |
5 | 141132202214433 |
6 | 5110335413241 |
7 | 550232430133 |
oct | 124224710071 |
9 | 32173005417 |
10 | 11313319993 |
11 | 488608a838 |
12 | 2238984221 |
13 | 10b3b0a1b1 |
14 | 794750053 |
15 | 46332ec2d |
hex | 2a2539039 |
11313319993 has 4 divisors (see below), whose sum is σ = 11313786240. Its totient is φ = 11312853748.
The previous prime is 11313319957. The next prime is 11313320027. The reversal of 11313319993 is 39991331311.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11313319993 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11313319903) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 194605 + ... + 245962.
It is an arithmetic number, because the mean of its divisors is an integer number (2828446560).
Almost surely, 211313319993 is an apocalyptic number.
It is an amenable number.
11313319993 is a deficient number, since it is larger than the sum of its proper divisors (466247).
11313319993 is an equidigital number, since it uses as much as digits as its factorization.
11313319993 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 466246.
The product of its digits is 59049, while the sum is 43.
The spelling of 11313319993 in words is "eleven billion, three hundred thirteen million, three hundred nineteen thousand, nine hundred ninety-three".
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