Base | Representation |
---|---|
bin | 1010010010100001011010… |
… | …0011101110000011110001 |
3 | 1111001112122212212200120222 |
4 | 2210220112203232003301 |
5 | 2440324141003220423 |
6 | 40021134000142425 |
7 | 2245234450024262 |
oct | 244502643560361 |
9 | 44045585780528 |
10 | 11313322320113 |
11 | 3671a5356a520 |
12 | 1328720907a15 |
13 | 640ac33388c8 |
14 | 2b17d3b86969 |
15 | 1494437373c8 |
hex | a4a168ee0f1 |
11313322320113 has 8 divisors (see below), whose sum is σ = 12498031562880. Its totient is φ = 10154650643280.
The previous prime is 11313322320077. The next prime is 11313322320143. The reversal of 11313322320113 is 31102322331311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 11313322320113 - 242 = 6915275809009 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (11313322320143) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6509390570 + ... + 6509392307.
It is an arithmetic number, because the mean of its divisors is an integer number (1562253945360).
Almost surely, 211313322320113 is an apocalyptic number.
It is an amenable number.
11313322320113 is a deficient number, since it is larger than the sum of its proper divisors (1184709242767).
11313322320113 is a wasteful number, since it uses less digits than its factorization.
11313322320113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13018782967.
The product of its (nonzero) digits is 1944, while the sum is 26.
Adding to 11313322320113 its reverse (31102322331311), we get a palindrome (42415644651424).
The spelling of 11313322320113 in words is "eleven trillion, three hundred thirteen billion, three hundred twenty-two million, three hundred twenty thousand, one hundred thirteen".
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