1131334341201 has 6 divisors (see below), whose sum is σ = 1634149603970. Its totient is φ = 754222894128.

The previous prime is 1131334341199. The next prime is 1131334341253. The reversal of 1131334341201 is 1021434331311.

1131334341201 is a `hidden beast` number, since 1 + 1 + 313 + 3 + 4 + 341 + 2 + 0 + 1 = 666.

It can be written as a sum of positive squares in only one way, i.e., 1026474948801 + 104859392400 = 1013151^2 + 323820^2 .

It is not a de Polignac number, because 1131334341201 - 2¹ = 1131334341199 is a prime.

It is a super-2 number, since 2×1131334341201² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1131334343201) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 62851907836 + ... + 62851907853.

Almost surely, 2^{1131334341201} is an apocalyptic number.

It is an amenable number.

1131334341201 is a deficient number, since it is larger than the sum of its proper divisors (502815262769).

1131334341201 is a wasteful number, since it uses less digits than its factorization.

1131334341201 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 125703815695 (or 125703815692 counting only the distinct ones).

The product of its (nonzero) digits is 2592, while the sum is 27.

Adding to 1131334341201 its reverse (1021434331311), we get a palindrome (2152768672512).

The spelling of 1131334341201 in words is "one trillion, one hundred thirty-one billion, three hundred thirty-four million, three hundred forty-one thousand, two hundred one".