Base | Representation |
---|---|
bin | 1010010010100001011111… |
… | …1111010100100111101001 |
3 | 1111001112201120001200022010 |
4 | 2210220113333110213221 |
5 | 2440324213130130121 |
6 | 40021140214550133 |
7 | 2245235161106205 |
oct | 244502777244751 |
9 | 44045646050263 |
10 | 11313346333161 |
11 | 3671a66080914 |
12 | 1328728968349 |
13 | 640ac82c5802 |
14 | 2b17d7037b05 |
15 | 1494458cc376 |
hex | a4a17fd49e9 |
11313346333161 has 4 divisors (see below), whose sum is σ = 15084461777552. Its totient is φ = 7542230888772.
The previous prime is 11313346333127. The next prime is 11313346333187. The reversal of 11313346333161 is 16133364331311.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 11313346333161 - 211 = 11313346331113 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11313346333561) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1885557722191 + ... + 1885557722196.
It is an arithmetic number, because the mean of its divisors is an integer number (3771115444388).
Almost surely, 211313346333161 is an apocalyptic number.
It is an amenable number.
11313346333161 is a deficient number, since it is larger than the sum of its proper divisors (3771115444391).
11313346333161 is an equidigital number, since it uses as much as digits as its factorization.
11313346333161 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3771115444390.
The product of its digits is 104976, while the sum is 39.
The spelling of 11313346333161 in words is "eleven trillion, three hundred thirteen billion, three hundred forty-six million, three hundred thirty-three thousand, one hundred sixty-one".
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