Base | Representation |
---|---|
bin | 1010010010100001110100… |
… | …1111000110000111101011 |
3 | 1111001112221200200121101221 |
4 | 2210220131033012013223 |
5 | 2440324403143313110 |
6 | 40021153041322511 |
7 | 2245240310220163 |
oct | 244503517060753 |
9 | 44045850617357 |
10 | 11313434354155 |
11 | 367200083033a |
12 | 1328752336437 |
13 | 640b10603a3b |
14 | 2b18049cb5a3 |
15 | 14944d4b77da |
hex | a4a1d3c61eb |
11313434354155 has 16 divisors (see below), whose sum is σ = 13600340715744. Its totient is φ = 9034609167360.
The previous prime is 11313434354149. The next prime is 11313434354197. The reversal of 11313434354155 is 55145343431311.
11313434354155 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11313434354155 - 23 = 11313434354147 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10844737 + ... + 11842093.
It is an arithmetic number, because the mean of its divisors is an integer number (850021294734).
Almost surely, 211313434354155 is an apocalyptic number.
11313434354155 is a deficient number, since it is larger than the sum of its proper divisors (2286906361589).
11313434354155 is an equidigital number, since it uses as much as digits as its factorization.
11313434354155 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1001406.
The product of its digits is 648000, while the sum is 43.
Adding to 11313434354155 its reverse (55145343431311), we get a palindrome (66458777785466).
The spelling of 11313434354155 in words is "eleven trillion, three hundred thirteen billion, four hundred thirty-four million, three hundred fifty-four thousand, one hundred fifty-five".
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