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113134404011 = 118195795431
BaseRepresentation
bin110100101011101010…
…1100000000110101011
3101211000112100012100112
41221113111200012223
53323144401412021
6123550114524535
711113401365366
oct1512725400653
9354015305315
10113134404011
1143a86470252
1219b1459674b
13a88c9ac635
1456935b50dd
152e22389d5b
hex1a575601ab

113134404011 has 4 divisors (see below), whose sum is σ = 113230200624. Its totient is φ = 113038607400.

The previous prime is 113134403983. The next prime is 113134404043. The reversal of 113134404011 is 110404431311.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 110404431311 = 671647827333.

It is a cyclic number.

It is not a de Polignac number, because 113134404011 - 210 = 113134402987 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (113134404091) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 47896535 + ... + 47898896.

It is an arithmetic number, because the mean of its divisors is an integer number (28307550156).

Almost surely, 2113134404011 is an apocalyptic number.

113134404011 is a deficient number, since it is larger than the sum of its proper divisors (95796613).

113134404011 is an equidigital number, since it uses as much as digits as its factorization.

113134404011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 95796612.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 113134404011 its reverse (110404431311), we get a palindrome (223538835322).

The spelling of 113134404011 in words is "one hundred thirteen billion, one hundred thirty-four million, four hundred four thousand, eleven".

Divisors: 1 1181 95795431 113134404011