Base | Representation |
---|---|
bin | 10101000100101010… |
… | …10111001001001011 |
3 | 1002012110020110202100 |
4 | 22202111113021023 |
5 | 141132220142103 |
6 | 5110342204443 |
7 | 550233453003 |
oct | 124225271113 |
9 | 32173213670 |
10 | 11313443403 |
11 | 4886164529 |
12 | 2238a23723 |
13 | 10b3b51412 |
14 | 794783003 |
15 | 4633565a3 |
hex | 2a255724b |
11313443403 has 6 divisors (see below), whose sum is σ = 16341640484. Its totient is φ = 7542295596.
The previous prime is 11313443399. The next prime is 11313443411. The reversal of 11313443403 is 30434431311.
11313443403 is a `hidden beast` number, since 1 + 1 + 313 + 4 + 4 + 340 + 3 = 666.
It is not a de Polignac number, because 11313443403 - 22 = 11313443399 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11313443443) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 628524625 + ... + 628524642.
Almost surely, 211313443403 is an apocalyptic number.
11313443403 is a deficient number, since it is larger than the sum of its proper divisors (5028197081).
11313443403 is a wasteful number, since it uses less digits than its factorization.
11313443403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1257049273 (or 1257049270 counting only the distinct ones).
The product of its (nonzero) digits is 5184, while the sum is 27.
Adding to 11313443403 its reverse (30434431311), we get a palindrome (41747874714).
The spelling of 11313443403 in words is "eleven billion, three hundred thirteen million, four hundred forty-three thousand, four hundred three".
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