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11314041 = 33771347
BaseRepresentation
bin101011001010…
…001101111001
3210021210221120
4223022031321
510344022131
61042255453
7165111354
oct53121571
923253846
1011314041
116428452
123957589
1324619cb
14170729b
15ed7496
hexaca379

11314041 has 4 divisors (see below), whose sum is σ = 15085392. Its totient is φ = 7542692.

The previous prime is 11314033. The next prime is 11314067. The reversal of 11314041 is 14041311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11314041 - 23 = 11314033 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11314041.

It is not an unprimeable number, because it can be changed into a prime (11314081) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1885671 + ... + 1885676.

It is an arithmetic number, because the mean of its divisors is an integer number (3771348).

Almost surely, 211314041 is an apocalyptic number.

It is an amenable number.

11314041 is a deficient number, since it is larger than the sum of its proper divisors (3771351).

11314041 is an equidigital number, since it uses as much as digits as its factorization.

11314041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3771350.

The product of its (nonzero) digits is 48, while the sum is 15.

The square root of 11314041 is about 3363.6350872233. The cubic root of 11314041 is about 224.4946088589.

Adding to 11314041 its reverse (14041311), we get a palindrome (25355352).

The spelling of 11314041 in words is "eleven million, three hundred fourteen thousand, forty-one".

Divisors: 1 3 3771347 11314041