Base | Representation |
---|---|
bin | 10101000100110001… |
… | …01000010001100001 |
3 | 1002012111211222210012 |
4 | 22202120220101201 |
5 | 141132430100001 |
6 | 5110412414305 |
7 | 550243651244 |
oct | 124230502141 |
9 | 32174758705 |
10 | 11314300001 |
11 | 488669a064 |
12 | 2239177395 |
13 | 10b4091294 |
14 | 79492725b |
15 | 4634752bb |
hex | 2a2628461 |
11314300001 has 4 divisors (see below), whose sum is σ = 11806226112. Its totient is φ = 10822373892.
The previous prime is 11314299977. The next prime is 11314300007. The reversal of 11314300001 is 10000341311.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10000341311 = 43 ⋅232566077.
It is a cyclic number.
It is not a de Polignac number, because 11314300001 - 218 = 11314037857 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (11314300007) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 245963021 + ... + 245963066.
It is an arithmetic number, because the mean of its divisors is an integer number (2951556528).
Almost surely, 211314300001 is an apocalyptic number.
It is an amenable number.
11314300001 is a deficient number, since it is larger than the sum of its proper divisors (491926111).
11314300001 is an equidigital number, since it uses as much as digits as its factorization.
11314300001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 491926110.
The product of its (nonzero) digits is 36, while the sum is 14.
Adding to 11314300001 its reverse (10000341311), we get a palindrome (21314641312).
The spelling of 11314300001 in words is "eleven billion, three hundred fourteen million, three hundred thousand, one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •