1131433433 has 4 divisors (see below), whose sum is σ = 1218466788. Its totient is φ = 1044400080.

The previous prime is 1131433427. The next prime is 1131433439. The reversal of 1131433433 is 3343341311.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (1131433427) and next prime (1131433439).

It can be written as a sum of positive squares in 2 ways, for example, as 109160704 + 1022272729 = 10448^2 + 31973^2 .

It is a cyclic number.

It is not a de Polignac number, because 1131433433 - 2¹⁰ = 1131432409 is a prime.

It is a super-2 number, since 2×1131433433² = 2560283226620330978, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1131433439) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43516658 + ... + 43516683.

It is an arithmetic number, because the mean of its divisors is an integer number (304616697).

Almost surely, 2^1131433433 is an apocalyptic number.

1131433433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

1131433433 is a deficient number, since it is larger than the sum of its proper divisors (87033355).

1131433433 is an equidigital number, since it uses as much as digits as its factorization.

1131433433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 87033354.

The product of its digits is 3888, while the sum is 26.

The square root of 1131433433 is about 33636.7869006539. The cubic root of 1131433433 is about 1042.0206747396.

Adding to 1131433433 its reverse (3343341311), we get a palindrome (4474774744).

The spelling of 1131433433 in words is "one billion, one hundred thirty-one million, four hundred thirty-three thousand, four hundred thirty-three".