Base | Representation |
---|---|
bin | 1010010010100101001101… |
… | …1001110001010111101011 |
3 | 1111001122022000200211002111 |
4 | 2210221103121301113223 |
5 | 2440333233314404121 |
6 | 40021423143343151 |
7 | 2245301653505260 |
oct | 244512331612753 |
9 | 44048260624074 |
10 | 11314343122411 |
11 | 367242780138a |
12 | 1328966751ab7 |
13 | 640c2697a434 |
14 | 2b188d58b267 |
15 | 1494a31772e1 |
hex | a4a536715eb |
11314343122411 has 16 divisors (see below), whose sum is σ = 13086821873664. Its totient is φ = 9580906675584.
The previous prime is 11314343122399. The next prime is 11314343122417. The reversal of 11314343122411 is 11422134341311.
It is a cyclic number.
It is not a de Polignac number, because 11314343122411 - 213 = 11314343114219 is a prime.
It is not an unprimeable number, because it can be changed into a prime (11314343122417) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 23100486 + ... + 23585188.
It is an arithmetic number, because the mean of its divisors is an integer number (817926367104).
Almost surely, 211314343122411 is an apocalyptic number.
11314343122411 is a deficient number, since it is larger than the sum of its proper divisors (1772478751253).
11314343122411 is an equidigital number, since it uses as much as digits as its factorization.
11314343122411 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 524970.
The product of its digits is 6912, while the sum is 31.
Adding to 11314343122411 its reverse (11422134341311), we get a palindrome (22736477463722).
The spelling of 11314343122411 in words is "eleven trillion, three hundred fourteen billion, three hundred forty-three million, one hundred twenty-two thousand, four hundred eleven".
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