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113144131 = 657717203
BaseRepresentation
bin1101011111001…
…11000101000011
321212220022120101
412233213011003
5212431103011
615121023231
72542465162
oct657470503
9255808511
10113144131
1158959951
1231a84b17
131a5964b9
14110533d9
159dee2c1
hex6be7143

113144131 has 4 divisors (see below), whose sum is σ = 113167912. Its totient is φ = 113120352.

The previous prime is 113144093. The next prime is 113144147. The reversal of 113144131 is 131441311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 113144131 - 223 = 104755523 is a prime.

It is a super-2 number, since 2×1131441312 = 25603188759490322, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 113144099 and 113144108.

It is not an unprimeable number, because it can be changed into a prime (113144191) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2025 + ... + 15178.

It is an arithmetic number, because the mean of its divisors is an integer number (28291978).

Almost surely, 2113144131 is an apocalyptic number.

113144131 is a deficient number, since it is larger than the sum of its proper divisors (23781).

113144131 is an equidigital number, since it uses as much as digits as its factorization.

113144131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 23780.

The product of its digits is 144, while the sum is 19.

The square root of 113144131 is about 10636.9230043279. The cubic root of 113144131 is about 483.6642752392.

Adding to 113144131 its reverse (131441311), we get a palindrome (244585442).

The spelling of 113144131 in words is "one hundred thirteen million, one hundred forty-four thousand, one hundred thirty-one".

Divisors: 1 6577 17203 113144131