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1131443140211 = 7477151323143
BaseRepresentation
bin10000011101101111010…
…001000011011001110011
311000011110012212210022022
4100131233101003121303
5122014143420441321
62223440001102055
7144513134003156
oct20355721033163
94004405783268
101131443140211
113a692a17968a
1216334602792b
1382905144a97
143ca95453c9d
151e671141dab
hex1076f443673

1131443140211 has 4 divisors (see below), whose sum is σ = 1131594470832. Its totient is φ = 1131291809592.

The previous prime is 1131443140189. The next prime is 1131443140249. The reversal of 1131443140211 is 1120413441311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1131443140211 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1131443140291) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 75654095 + ... + 75669048.

It is an arithmetic number, because the mean of its divisors is an integer number (282898617708).

Almost surely, 21131443140211 is an apocalyptic number.

1131443140211 is a deficient number, since it is larger than the sum of its proper divisors (151330621).

1131443140211 is an equidigital number, since it uses as much as digits as its factorization.

1131443140211 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 151330620.

The product of its (nonzero) digits is 1152, while the sum is 26.

Adding to 1131443140211 its reverse (1120413441311), we get a palindrome (2251856581522).

The spelling of 1131443140211 in words is "one trillion, one hundred thirty-one billion, four hundred forty-three million, one hundred forty thousand, two hundred eleven".

Divisors: 1 7477 151323143 1131443140211