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113144532153 = 337714844051
BaseRepresentation
bin110100101011111110…
…0001000110010111001
3101211001020101202112220
41221113330020302321
53323210000012103
6123551115554253
711113553440452
oct1512774106271
9354036352486
10113144532153
1143a91158714
1219b17a5b989
13a891b17613
145694a90129
152e231dac53
hex1a57f08cb9

113144532153 has 4 divisors (see below), whose sum is σ = 150859376208. Its totient is φ = 75429688100.

The previous prime is 113144532131. The next prime is 113144532167. The reversal of 113144532153 is 351235441311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 113144532153 - 214 = 113144515769 is a prime.

It is a super-2 number, since 2×1131445321532 (a number of 23 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (113144532653) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18857422023 + ... + 18857422028.

It is an arithmetic number, because the mean of its divisors is an integer number (37714844052).

Almost surely, 2113144532153 is an apocalyptic number.

It is an amenable number.

113144532153 is a deficient number, since it is larger than the sum of its proper divisors (37714844055).

113144532153 is an equidigital number, since it uses as much as digits as its factorization.

113144532153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 37714844054.

The product of its digits is 21600, while the sum is 33.

Adding to 113144532153 its reverse (351235441311), we get a palindrome (464379973464).

The spelling of 113144532153 in words is "one hundred thirteen billion, one hundred forty-four million, five hundred thirty-two thousand, one hundred fifty-three".

Divisors: 1 3 37714844051 113144532153