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11315402713 = 23491974031
BaseRepresentation
bin10101000100111001…
…10101011111011001
31002012120221000102101
422202130311133121
5141133220341323
65110452203401
7550256223166
oct124234653731
932176830371
1011315402713
11488728259a
122239609561
1310b4389184
14794b3306d
154635e1dad
hex2a27357d9

11315402713 has 4 divisors (see below), whose sum is σ = 11807376768. Its totient is φ = 10823428660.

The previous prime is 11315402701. The next prime is 11315402719. The reversal of 11315402713 is 31720451311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11315402713 - 217 = 11315271641 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11315402719) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 245986993 + ... + 245987038.

It is an arithmetic number, because the mean of its divisors is an integer number (2951844192).

Almost surely, 211315402713 is an apocalyptic number.

It is an amenable number.

11315402713 is a deficient number, since it is larger than the sum of its proper divisors (491974055).

11315402713 is an equidigital number, since it uses as much as digits as its factorization.

11315402713 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 491974054.

The product of its (nonzero) digits is 2520, while the sum is 28.

The spelling of 11315402713 in words is "eleven billion, three hundred fifteen million, four hundred two thousand, seven hundred thirteen".

Divisors: 1 23 491974031 11315402713