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11315852353 = 13870450181
BaseRepresentation
bin10101000100111101…
…00011010001000001
31002012121202212012201
422202132203101001
5141133324233403
65110505553201
7550263105121
oct124236432101
932177685181
1011315852353
11488755a3a3
1222397a5801
1310b44b5a30
14794c0cc81
1546368021d
hex2a27a3441

11315852353 has 4 divisors (see below), whose sum is σ = 12186302548. Its totient is φ = 10445402160.

The previous prime is 11315852321. The next prime is 11315852357. The reversal of 11315852353 is 35325851311.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 35325851311 = 109324090379.

It can be written as a sum of positive squares in 2 ways, for example, as 3872821824 + 7443030529 = 62232^2 + 86273^2 .

It is a cyclic number.

It is not a de Polignac number, because 11315852353 - 25 = 11315852321 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11315852357) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 435225078 + ... + 435225103.

It is an arithmetic number, because the mean of its divisors is an integer number (3046575637).

Almost surely, 211315852353 is an apocalyptic number.

11315852353 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

11315852353 is a deficient number, since it is larger than the sum of its proper divisors (870450195).

11315852353 is an equidigital number, since it uses as much as digits as its factorization.

11315852353 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 870450194.

The product of its digits is 54000, while the sum is 37.

The spelling of 11315852353 in words is "eleven billion, three hundred fifteen million, eight hundred fifty-two thousand, three hundred fifty-three".

Divisors: 1 13 870450181 11315852353