1132002313321 has 4 divisors (see below), whose sum is σ = 1234911614544. Its totient is φ = 1029093012100.

The previous prime is 1132002313319. The next prime is 1132002313327. The reversal of 1132002313321 is 1233132002311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1132002313321 - 2¹ = 1132002313319 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1132002313292 and 1132002313301.

It is not an unprimeable number, because it can be changed into a prime (1132002313327) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 51454650595 + ... + 51454650616.

It is an arithmetic number, because the mean of its divisors is an integer number (308727903636).

Almost surely, 2^{1132002313321} is an apocalyptic number.

1132002313321 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

1132002313321 is a deficient number, since it is larger than the sum of its proper divisors (102909301223).

1132002313321 is a wasteful number, since it uses less digits than its factorization.

1132002313321 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 102909301222.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 1132002313321 its reverse (1233132002311), we get a palindrome (2365134315632).

The spelling of 1132002313321 in words is "one trillion, one hundred thirty-two billion, two million, three hundred thirteen thousand, three hundred twenty-one".