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11320030132003 = 45526924864487
BaseRepresentation
bin1010010010111010011001…
…0111111111011100100011
31111002011222100210211122101
42210232212113333130203
52440431410203211003
640024203335551231
72245562620341205
oct244564627773443
944064870724571
1011320030132003
11367488599590a
121329a9322b517
13641621c4a678
142b1c6c9a4775
151496d758711d
hexa4ba65ff723

11320030132003 has 4 divisors (see below), whose sum is σ = 11320055451760. Its totient is φ = 11320004812248.

The previous prime is 11320030131989. The next prime is 11320030132027. The reversal of 11320030132003 is 30023103002311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11320030132003 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11320030132063) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11976975 + ... + 12887512.

It is an arithmetic number, because the mean of its divisors is an integer number (2830013862940).

Almost surely, 211320030132003 is an apocalyptic number.

11320030132003 is a deficient number, since it is larger than the sum of its proper divisors (25319757).

11320030132003 is an equidigital number, since it uses as much as digits as its factorization.

11320030132003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 25319756.

The product of its (nonzero) digits is 324, while the sum is 19.

Adding to 11320030132003 its reverse (30023103002311), we get a palindrome (41343133134314).

The spelling of 11320030132003 in words is "eleven trillion, three hundred twenty billion, thirty million, one hundred thirty-two thousand, three".

Divisors: 1 455269 24864487 11320030132003