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11320112003 = 79307466751
BaseRepresentation
bin10101000101011101…
…10011001110000011
31002012220210021100112
422202232303032003
5141140422041003
65111141141535
7550344235664
oct124256631603
932186707315
1011320112003
1148899a9772
12223b0ba8ab
1310b5347835
147955db36b
15463c223d8
hex2a2bb3383

11320112003 has 8 divisors (see below), whose sum is σ = 11500769280. Its totient is φ = 11140389000.

The previous prime is 11320111961. The next prime is 11320112029. The reversal of 11320112003 is 30021102311.

11320112003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11320112003 - 216 = 11320046467 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11320112033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 209123 + ... + 257628.

It is an arithmetic number, because the mean of its divisors is an integer number (1437596160).

Almost surely, 211320112003 is an apocalyptic number.

11320112003 is a deficient number, since it is larger than the sum of its proper divisors (180657277).

11320112003 is an equidigital number, since it uses as much as digits as its factorization.

11320112003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 467137.

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 11320112003 its reverse (30021102311), we get a palindrome (41341214314).

The spelling of 11320112003 in words is "eleven billion, three hundred twenty million, one hundred twelve thousand, three".

Divisors: 1 79 307 24253 466751 36873329 143292557 11320112003