1132011212131 has 4 divisors (see below), whose sum is σ = 1140274067832. Its totient is φ = 1123748356432.

The previous prime is 1132011212113. The next prime is 1132011212141. The reversal of 1132011212131 is 1312121102311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1132011212131 - 2⁵ = 1132011212099 is a prime.

It is a super-2 number, since 2×1132011212131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1132011212099 and 1132011212108.

It is not an unprimeable number, because it can be changed into a prime (1132011212141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4131427645 + ... + 4131427918.

It is an arithmetic number, because the mean of its divisors is an integer number (285068516958).

Almost surely, 2^{1132011212131} is an apocalyptic number.

1132011212131 is a deficient number, since it is larger than the sum of its proper divisors (8262855701).

1132011212131 is an equidigital number, since it uses as much as digits as its factorization.

1132011212131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8262855700.

The product of its (nonzero) digits is 72, while the sum is 19.

Adding to 1132011212131 its reverse (1312121102311), we get a palindrome (2444132314442).

The spelling of 1132011212131 in words is "one trillion, one hundred thirty-two billion, eleven million, two hundred twelve thousand, one hundred thirty-one".